145 Fun Facts About Elephants That Will Blow Your Mind

145 Fun Facts About Elephants That Will Blow Your Mind

145 Fun Facts About Elephants That Will Blow Your Mind What we're really doing here is that we're given an initial state with # ["brcl"] i = "0.050 m"#, and we're given #k (eq)#, which is defined for a final state we define as equilibrium, when the rate of the forward reaction is equal to that of the reverse reaction. Explanation: to eliminate the fractions in the equation, multiply all terms on both sides by the #color (blue)"lowest common multiple"# (lcm) of 5 ,14 and 7, the values on the denominators.

145 Fun Facts About Elephants That Will Blow Your Mind

145 Fun Facts About Elephants That Will Blow Your Mind First, subtract #color (red) ($145)# from each side of the equation to isolate the #w# term while keeping the equation balanced:. Maria had 105 beads to start with. first define the number of beads each girl had using variables. let the number of beads that maria had be x together they had 250, so the number of beads that farida had is 250 x maria uses 18 beads, so she has (x 18) left farida gives 2/5 of her beads away, so she has 3/5(250 x) left now they have the same number of beads: x 18 = 3/5(250 x)" "larr multiply. 196 ft.^2 refer to figures below from the given data we have d 1=6 ft. => r 1=3ft. d 2=4 fl. => r 2=2ft. h=12ft. as we can see in fig. (a) r 2/(h h)=r 1/h 2/(h 12)=3/h => 2h=3h 36 => h=36 since s=sqrt(2)*r (see fig.(b)) s 1=3sqrt(2) s 2=2sqrt(2 area of bases s (b1)=s 1^2=(3sqrt(2))^2=18 s (b2)=s 2^2=(2sqrt(2))^2=8 side of the slanted trapezoid (see fig.(c)) x^2=h^2 (r 1 r 2)^2 x=sqrt(12^2 1^2. The sum of the first nth term of a geometric series is 145 and the sum of the reciprocal is 145/33. the first term is 1. what is n and the common ratio? precalculus.

145 Fun Facts About Elephants That Will Blow Your Mind

145 Fun Facts About Elephants That Will Blow Your Mind 196 ft.^2 refer to figures below from the given data we have d 1=6 ft. => r 1=3ft. d 2=4 fl. => r 2=2ft. h=12ft. as we can see in fig. (a) r 2/(h h)=r 1/h 2/(h 12)=3/h => 2h=3h 36 => h=36 since s=sqrt(2)*r (see fig.(b)) s 1=3sqrt(2) s 2=2sqrt(2 area of bases s (b1)=s 1^2=(3sqrt(2))^2=18 s (b2)=s 2^2=(2sqrt(2))^2=8 side of the slanted trapezoid (see fig.(c)) x^2=h^2 (r 1 r 2)^2 x=sqrt(12^2 1^2. The sum of the first nth term of a geometric series is 145 and the sum of the reciprocal is 145/33. the first term is 1. what is n and the common ratio? precalculus. 12.04 (approx) let the length of side a or b = x and base is 16. so the height is sqrt [x^2 (16/2)^2] now the area of triangle = 1/2 * base * height = 1/2 * 16 * sqrt [x^2 (16/2)^2]. therefore, 1/2 * 16 * sqrt [x^2 (16/2)^2] = 72 or, sqrt [x^2 8^2]=72/8 or, x^2 64 = 81 or, x^2 = 145 or, x = sqrt 145 = 12.04 (approx). No real solutions. calling alpha = 4x y we have { (sqrtx (1 alpha)=2), (sqrty (1 alpha)=6):} then 2 alpha = (1 alpha)^2 (1 alpha)^2=36/y 4/x or 4x y = 9/y 1/x we. Just q8. i'll ask more questions if i need more help. => x = 10 the measures (angles) of a triangle sum to 180^o. =>90 55 (3x 5) = 180 =>145 (3x 5)=180 =>3x 5 = 35 =>3x = 30 => x = 10.

Fun Facts About Elephants For Kids - Mama Teaches

Fun Facts About Elephants For Kids - Mama Teaches 12.04 (approx) let the length of side a or b = x and base is 16. so the height is sqrt [x^2 (16/2)^2] now the area of triangle = 1/2 * base * height = 1/2 * 16 * sqrt [x^2 (16/2)^2]. therefore, 1/2 * 16 * sqrt [x^2 (16/2)^2] = 72 or, sqrt [x^2 8^2]=72/8 or, x^2 64 = 81 or, x^2 = 145 or, x = sqrt 145 = 12.04 (approx). No real solutions. calling alpha = 4x y we have { (sqrtx (1 alpha)=2), (sqrty (1 alpha)=6):} then 2 alpha = (1 alpha)^2 (1 alpha)^2=36/y 4/x or 4x y = 9/y 1/x we. Just q8. i'll ask more questions if i need more help. => x = 10 the measures (angles) of a triangle sum to 180^o. =>90 55 (3x 5) = 180 =>145 (3x 5)=180 =>3x 5 = 35 =>3x = 30 => x = 10.

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